Compensation Theorem
This theorem is based on one basic concept. According to Ohm’s law , whencurrent flows through any resistor, there would be a voltage drop across theresistor . This dropped voltage opposes the source voltage. Hence voltage drop across a resistance in any network can be assumed as a voltage source acting opposite to the source voltage. Thecompensation theorem depends upon this concept.
Here in the network for 16 V source, all the currents flowing through the different resistive branches are shown in the first figure. The current through the right most branch in the figure is 2A and its resistance is 2 Ω. If this right most branch of the network is replaced by avoltage source V = 2ΩX2A = 4V directed as shown in the second figure, then current through the other branches of the network will remain the same as shown in the second figure.
According to this theorem, anyresistance in a network may be replaced by a voltage source that has zero internal resistance and a voltage equal to the voltage drop across the replaceresistance due to the current which was flowing through it. This imaginaryvoltage source is directed opposite to the voltage source of that replacedresistance. Think about a resistive branch of any complex network that's resistance value is R. Let's assume current I is flowing through that resistor R and voltage drops due to thiscurrent across the resistor is V = I.R. According to compensation theorem, this resistor can be replaced by a voltage source that's generated voltage will be V ( = IR) and will be directed against the direction of network voltage or direction of current I.
The compensation theorem can easily be understood by this following example.
Here in the network for 16 V source, all the currents flowing through the different resistive branches are shown in the first figure. The current through the right most branch in the figure is 2A and its resistance is 2 Ω. If this right most branch of the network is replaced by avoltage source V = 2ΩX2A = 4V directed as shown in the second figure, then current through the other branches of the network will remain the same as shown in the second figure.
No comments:
Post a Comment